1. What is another name to describe "angle points of non-riparian meander lines?"

 a. Water boundary adjustment
 b. Meander line adjustment
 c. Compass rule adjustment or nonriparian broken boundary adjustment

2. The above adjustment method distributes what measurement proportionately along each course?

 a. The error of closure
 b. Then closing error
 c. The error in departure

3. What kind of corners are used to control a non-riparian meander line adjustment?
 
 a. Meander corners
 b. Closing corners
 c. Senior corners

4. One assumption is that any errors in the original survey were accidental. The second assumption is that the effects of angular errors equal the effects of

 a. Instrument error.
 b. Blunders.
 c. Chaining errors.

5. Using the formulas you completed above, calculate the bearings, distances, and moves of the two courses in this lost nonriparian meander line. Record was run with a tie to the other known corner.

Course 1

 a. N 71° 35' W 18.607
 b. N 72° 05' E 18.156
 c. N 71° 08' W 17.118

Course 1

 a. N 09° 35' E 11.607
 b. N 09° 50' E 11.046
 c. N 08° 45' E 11.055

Correct Answers for Unit 4 Section 1 Review Exercise:

1. What is another name to describe "angle points of non-riparian meander lines?" 

Correct Answer: c. Compass rule adjustment or nonriparian broken boundary adjustment.

2. The above adjustment method distributes what measurement proportionately along each course?

Correct Answer: b. Then closing error

3. What kind of corners are used to control a non?riparian meander line adjustment?
 
Correct Answer: a. Meander corners

4. One assumption is that any errors in the original survey were accidental. The second assumption is that the effects of angular errors equal the effects of

Correct Answer: c. Chaining errors

5. Using the formulas you completed above, calculate the bearings, distances, and moves of the two courses in this lost nonriparian meander line. Record was run with a tie to the other known corner.

Course 1
Correct Answer: c. N 71° 08' W 17.118 

Course 1
Correct Answer: b. N 09° 50' E 11.046